vitorio Posted December 13, 2019 Share Posted December 13, 2019 The two hikers set off at 6am. They pass each other at midday after X hours of walking. Bonnie has 4 more hours to go and Aaron has 9. The distance Bonnie has travelled is equal to the distance that Aaron is yet to travel. How many hours of walking done? Good luck! Will post solution later on with explation why.👍 Link to comment Share on other sites More sharing options...
vitorio Posted December 15, 2019 Author Share Posted December 15, 2019 Solution: Assuming constant walking speeds for both hikers, then the time Bonnie has travelled divided by the time she has left to travel is X/4. For Aaron, the time he has yet to travel divided by the time he has travelled is 9/X. These two are equal, hence X2 =9x4=36, soX=6. Link to comment Share on other sites More sharing options...
Karlston Posted December 24, 2019 Share Posted December 24, 2019 Isn’t it easier than that? If they set off at 6am and meet at midday, then they’ve each walked for (12 - 6) hours = 6 hours? And midday doesn’t have to be on the same day as they started, so 30 (6 +24), 54 (6 + 2 x 24), etc are also answers? BTW, I edited your post to change the X2 to X2 Link to comment Share on other sites More sharing options...
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